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pression The middle name expression matches zero or more occurrences of whitespace followed by a word The second part of the regex, \s+(\w+), matches the whitespace that follows the forename (and middle names) and the surname If the regex looks a bit too much like line noise, we can use named capture groups to improve legibility and make it more maintainable:

reader()

java FilterSearch localhost 389 "" "" "o=airiuscom" "(cn~=brian)"

name = resub(r"( P<forenames>\w+( :\s+\w+)*)" r"\s+( P<surname>\w+)", r"\g<surname>, \g<forenames>", name)

Because writer() writes f after the object's constructor nishes, the reader() will be guaranteed to see the properly initialized value for fx: it will read the value 3 However, fy is not nal; the reader() method is therefore not guaranteed to see the value 4 for it

This search uses the sounds like operator (see Table 5-1) The following results will be displayed:

.

Final elds are designed to allow for necessary security guarantees Consider the following example One thread (which we shall refer to as thread 1) executes

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Captured text can be referred to in a sub() or subn() function or method by using the syntax \i or \g<id> where i is the number of the capture group and id is the name or number of the capture group so \1 is the same as \g<1>, and in this example, the same as \g<forenames> This syntax can also be used in the string passed to a match object s expand() method Why doesn t the rst part of the regex grab the entire name After all, it is using greedy matching In fact it will, but then the match will fail because although the middle names part can match zero or more times, the surname part must match exactly once, but the greedy middle names part has grabbed everything Having failed, the regular expression engine will then backtrack, giving up the last middle name and thus allowing the surname to match Although greedy matches match as much as possible, they stop if matching more would make the match fail For example, if the name is John le Carr , the regex will rst match the entire name, that is, John le Carr This satis es the rst part of the regex but leaves nothing for the surname part to match, and since the surname is mandatory (it has an implicit quanti er of 1), the regex has failed Since the middle names part is quanti ed by *, it can match zero or more times (currently it is matching twice, le and Carr ), so the regular expression engine can make it give up some of its match without causing it to fail Therefore, the regex backtracks, giving up the last \s+\w+ (ie, Carr ), so the match becomes John le Carr with the match satisfying the whole regex and with the two match groups containing the correct texts There s one weakness in the regex as written: It doesn t cope correctly with forenames that are written using an initial, such as James W Loewen , or J R R Tolkein This is because \w matches word characters and these don t include period One obvious but incorrect solution is to change the forenames part of the regex s \w+ expression to [\w]+, in both places that it occurs A period in a character class is taken to be a literal period, and character class shorthands retain their meaning inside character classes, so the new expression matches word characters or periods But this would allow for names like , , A , A , and so on In view of this, a more subtle approach is required.

Globals = "/tmp/usr"substring(4);

Search filter=(cn~=brian) DN: uid=bplante, ou=People, o=airiuscom cn: Brian Plante mail: bplante@airiuscom telephoneNumber: +1 408 555 3550 DN: uid=jbrown, ou=People, o=airiuscom cn: Judy Brown mail: jbrown@airiuscom telephoneNumber: +1 408 555 6885

Syntax mend(g)

String myS = Globals; if (mySequals("/tmp"))Systemoutprintln(myS);

The results indicate that Brown sounds close to Brian according to the syntax rules of the server, and of course Brian was found as well

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